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AD9516-2/PCBZ Fiches technique(PDF) 45 Page - Analog Devices |
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AD9516-2/PCBZ Fiches technique(HTML) 45 Page - Analog Devices |
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45 / 84 page ![]() AD9516-2 Rev. 0 | Page 45 of 84 By cascading the dividers, channel division up to 1024 can be obtained. However, not all integer value divisions from 1 to 1024 are obtainable; only the values that are the product of the separate divisions of the two dividers (DX.1 × DX.2) can be realized. If only one divider is needed when using Divider 3 and Divider 4, use the first one (X.1) and bypass the second one (X.2). Do not bypass X.1 and use X.2. Duty Cycle and Duty-Cycle Correction (Divider 3 and Divider 4) The same duty cycle and DCC considerations apply to Divider 3 and Divider 4 as to Divider 0, Divider 1, and Divider 2 (see Duty Cycle and Duty-Cycle Correction (0, 1, and 2)); however, with these channel dividers, the number of possible configurations is even more complex. Duty-cycle correction on Divider 3 and Divider 4 requires the following channel divider conditions: • An even D X.Y must be set as MX.Y = NX.Y (low cycles = high cycles). • An odd D X.Y must be set as MX.Y = NX.Y + 1 (the number of low cycles must be one greater than the number of high cycles). • If only one divider is bypassed, it must be the second divider, X.2. • If only one divider has an even divide by, it must be the second divider, X.2. The possibilities for the duty cycle of the output clock from Divider 3 and Divider 4 are shown in Table 40 through Table 44 Table 40. Divider 3and Divider 4 Duty Cycle; VCO Divider Used; Duty Cycle Correction Off (DCCOFF = 1) DX.1 DX.2 VCO Divider NX.1 + MX.1 + 2 NX.2 + MX.2 + 2 Output Duty Cycle Even 1 1 50% Odd = 3 1 1 33.3% Odd = 5 1 1 40% Even Even, Odd 1 (NX.1 + 1)/ (NX.1 + MX.1 + 2) Odd Even, Odd 1 (NX.1 + 1)/ (NX.1 + MX.1 + 2) Even Even, Odd Even, Odd (NX.2 + 1)/ (NX.2 + MX.2 + 2) Odd Even, Odd Even, Odd (NX.2 + 1)/ (NX.2 + MX.2 + 2) Table 41. Divider 3 and Divider 4 Duty Cycle; VCO Divider Not Used; Duty Cycle Correction Off (DCCOFF = 1) DX.1 DX.2 Input Clock Duty Cycle NX.1 + MX.1 + 2 NX.2 + MX.2 + 2 Output Duty Cycle 50% 1 1 50% X% 1 1 X% 50% Even, Odd 1 (NX.1 + 1)/ (NX.1 + MX.1 + 2) X% Even, Odd 1 (NX.1 + 1)/ (NX.1 + MX.1 + 2) 50% Even, Odd Even, Odd (NX.2 + 1)/ (NX.2 + MX.2 + 2) X% Even, Odd Even, Odd (NX.2 + 1)/ (NX.2 + MX.2 + 2) Table 42. Divider 3 and Divider 4 Duty Cycle; VCO Divider Used; Duty Cycle Correction Is On (DCCOFF = 0); VCO Divider Input Duty Cycle = 50% DX.1 DX.2 VCO Divider NX.1 + MX.1 + 2 NX.2 + MX.2 + 2 Output Duty Cycle Even 1 1 50% Odd 1 1 50% Even Even (NX.1 = MX.1) 1 50% Odd Even (NX.1 = MX.1) 1 50% Even Odd (MX.1 = NX.1 + 1) 1 50% Odd Odd (MX.1 = NX.1 + 1) 1 50% Even Even (NX.1 = MX.1) Even (NX.2 = MX.2) 50% Odd Even (NX.1 = MX.1) Even (NX.2 = MX.2) 50% Even Odd (MX.1 = NX.1 + 1) Even (NX.2 = MX.2) 50% Odd Odd (MX.1 = NX.1 + 1) Even (NX.2 = MX.2) 50% Even Odd (MX.1 = NX.1 + 1) Odd (MX.2 = NX.2 + 1) 50% Odd Odd (MX.1 = NX.1 + 1) Odd (MX.2 = NX.2 + 1) 50% |
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