EUP9232 datasheet(10/20 Pages) EUTECH

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EUP9232

DS9232 Ver1.1 Feb. 2007

TEST Circuits

(1) Test Condition 1, Test Circuit 1

Set S1=OFF, V1= V2 =3.6 V, and V3= 0 V under

normal condition. Increase V1 from 3.6V gradually. The

V1 voltage when CO = “L” is overcharge detection

voltage 1 (VCU1). Decrease V1 gradually. The V1

voltage when CO = “H” is overcharge release voltage

1(VCD1). Further decrease V1. The V1 voltage when

DO= “L” is overdischarge voltage 1(VDD1). Increase V1

gradually. The V1 voltage when DO = “H” is

overdischarge release voltage 1 (VDU1). Set S1 = ON,

and V1= V2= 3.6 V and V3 = 0 V under normal

condition. Increase V1 from 3.6V gradually. The V1

voltage when CO = “L” is auxiliary overcharge detection

voltage 1 (VCUaux1).

(2) Test Condition 2, Test Circuit 1

Set S1=OFF, V1= V2 =3.6 V, and V3= 0V under normal

condition. Increase V2 from 3.6V gradually. The V2

voltage when CO = “L” is overcharge detection voltage

2 (VCU2). Decrease V2 gradually. The V2 voltage when

CO = “H” is overcharge release voltage 2(VCD2). Further

decrease V2. The V2 voltage when DO= “L” is

overdischarge voltage 2(VDD2). Increase V2 gradually.

The V2 voltage when DO = “H” is overdischarge release

voltage 2 (VDU2). Set S1 = ON, and V1= V2= 3.6 V and

V3 = 0 V under normal condition. Increase V2 from 3.6V

gradually. The V2 voltage when CO = “L” is auxiliary

overcharge detection voltage 2 (VCUaux2).

(3) Test Condition 3, Test Circuit 1

Set S1=OFF, V1 =V2 =3.6 V, and V3 = 0V under

normal condition. Increase V3 from 0V gradually. The

V3 voltage when DO= “L” is overcurrent detection

voltage 1 (VIOV1). Set S1 =ON, V1=V2= 3.6V, V3=0

under normal condition. Increase V3 from 0 V

gradually.V3 voltage when DO= “L” is overcurrent

detection voltage 2 (VIOV2).

(4) Test Condition 4, Test Circuit 2

Set S1 = ON, V1 = V2 =3.6V, and V3 =0 V under

normal condition and measure current consumption.

Current consumption I1 is the normal condition current

consumption (IOPE). Set S1 =OFF, V1 =V2 =1.5V under

overdischarge

condition

and

measure

current

consumption.

Current

consumption

the

power-down current consumption (IPDN).

(5) Test Condition 5, Test Circuit 2

Set S1 =ON, V1=V2 = 1.5 V, and V3 =0 V under

overdischarge condition. (V1+V2)/I2 is the internal

resistance between VCC and VM (Rvcm).

Set S1= ON, V1=V2=3.5V, and V3 = 1.0 V under

overcurrent condition. V3 / I2 is the internal resistance

between VSS and VM (Rvsm).

(6) Test Condition 6, Test Circuit 3

Set S1=ON,

S2=OFF,V1=V2=3.6V, and V3 =0 V

under normal condition. Increase V4 from 0V gradually.

The V4 voltage when I1=10µA is DO voltage “H” (VDOH).

Set S1=OFF, S2=ON,V1=V2=3.6V, and V3=0.5 V

under overcurrent condition. Increase V5 from 0V

gradually. The V5 voltage when I2=10µA is DO voltage

“L” (VDOL).

(7) Test Condition 7, Test Circuit 4

Set S1 = ON, S2=OFF, V1=V2 =3.6V, and V3 =0 V

under normal condition. Increase V4 from 0V gradually.

The V4 voltage when I1=10µA is the CO “H” voltage

(VCOH).

Set S1=OFF, S2=ON,V1=4.4, V2 =3.6V, and V3 =0 V

under overcharge condition. Increase V4 from 0V

gradually. The V5 voltage when I1=10µA is CO voltage

“L” (VCOL).

(8) Test Condition 8, Test Circuit 5

Set V1=V2=3.6V and V3=0V under normal condition.

Increase

from

(VCU1-0.2V)

(VCU1+0.2V)

immediately (within 10µs). The time after V1 becomes

(VCU1+0.2V) until CO goes “L” is the overcharge

detection delay time 1 (tCU1).

Set V1=V2=3.5V and V3=0V under normal condition.

Decrease

from

(VDD1+0.2V)

(VDD1-0.2V)

immediately (within 10µs). The time after V1 becomes

(VDD1-0.2V) until DO goes “L” is the overcharge

detection delay time 1 (tDD1).

(9) Test Condition 9, Test Circuit 5

Set V1=V2=3.6V and V3=0V under normal condition.

Increase

from

(VCU2-0.2V)

(VCU2+0.2V)

immediately (within 10µs). The time after V2 becomes

(VCU2+0.2V) until CO goes “L” is the overcharge

detection delay time 2 (tCU2).

Set V1=V2=3.6V and V3=0V under normal condition.

Decrease

from

(VDD2+0.2V)

(VDD2-0.2V)

immediately (within 10µs). The time after V2 becomes

(VDD2-0.2V) until DO goes “L” is the overcharge

detection delay time 2 (tDD2).

(10) Test Condition 10, Test Circuit 5

Set V1=V2=3.6V and V3=0V under normal condition.

Increase V3 from 0V to 0.5V immediately(within 10µs).

The time after V3 becomes 0.5V until DO goes “L” is

the overcurrent detection delay time 1(tI0V1).

(11) Test Condition 11, Test Circuit 6

Set V1=V2=0V and V3=2V,and decrease V3 gradually.

The V3 voltage when CO=”L”(VCC-0.3V or lower) is the

0V charge starting voltage (V0CHA).

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