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ADE7858 Fiches technique(PDF) 33 Page - Analog Devices |
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ADE7858 Fiches technique(HTML) 33 Page - Analog Devices |
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33 / 76 page ![]() Preliminary Technical Data ADE7858 Rev. PrA | Page 33 of 76 arguments only, the result of the square root operation is erroneous, equal to 0x7FFFFF. It is recommended to avoid using big, negative VRMSOS values and as the equivalent rms value of a full-scale sinusoidal signal is 4,191,910(0x3FF6A6), much smaller than 0x7FFFFF, such values may be easily eliminated from consideration. As previously stated, the serial ports of the ADE7858 work on 32, 16 or 8-bit words and the DSP works on 28 bits. Similar to registers presented in Figure 15, AVRMSOS, BVRMSOS and CVRMSOS 24-bit registers are accessed as 32-bit registers with 4 most significant bits padded with 0s and sign extended to 28 bits. ACTIVE POWER CALCULATION The ADE7858 computes the total active power on every phase. Total active power considers in its calculation all fundamental and harmonic components of the voltages and currents. Total Active Power Calculation Electrical power is defined as the rate of energy flow from source to load. It is given by the product of the voltage and current waveforms. The resulting waveform is called the instantaneous power signal and it is equal to the rate of energy flow at every instant of time. The unit of power is the watt or joules/sec. If an ac system is supplied by a voltage v(t) and consumes the current i(t) and each of them contains harmonics, then: k 1 k k t k sin 2 V ) t ( v (16) k 1 k k t k sin 2 I ) t ( i where k V , k I = rms voltage and current of each harmonic, k , k =phase delays of each harmonic. The instantaneous power in an ac system is: m k 1 m , k m k m k m k k k 1 k k k 1 k k k k k t m k cos t m k cos I V t k 2 cos I V cos I V ) t ( i ) t ( v ) t ( p (17) The average power over an integral number of line cycles (n) is given by the expression in Equation (18). 1 k k k k k nT 0 cos I V dt t p nT 1 P (18) where: T is the line cycle period. P is referred to as the total active or total real power. Note that the total active power is equal to the dc component of the instantaneous power signal p(t) in expression (17), that is, 1 k k k k k cos I V . This is the expression used to calculate the total active power in the ADE7858 for each phase. Figure 38 shows how the ADE7858 computes the total active power on each phase. First, it multiplies the current and voltage signals in each phase. Then, extracts the dc component of the instantaneous power signal in each phase (A, B and C) using LPF2, the low pass filter. v A i A HPF HPF AVGAIN Digital Integrator AIGAIN APHCAL LPF AWATTOS Digital Signal Processor AWGAIN HPFDIS[23:0] HPFDIS[23:0] INSTANTANEOUS PHASE A ACTIVE POWER Figure 38. Total Active Power Data Path If the phase currents and voltages contain only the fundamental component, are in phase (that is 0 1 1 ) and they correspond to full scale ADC inputs, then multiplying them results in an instantaneous power signal that has a dc component 1 1 I V and a sinusoidal component t 2 cos I V 1 1 . Figure 39 shows the corresponding waveforms. 0x3FED4D6 = 67,032,278 0x000 0000 VRMS x IRMS 0x1FF6A6B = 33,516,139 INSTANTANEOUS POWER SIGNAL p(t)=VRMS x IRMS - VRMS x IRMS x cos(2wt) INSTANTANEOUS ACTIVE POWER SIGNAL: VRMS x IRMS ) t sin( IRMS 2 ) t ( i ) t sin( VRMS 2 ) t ( v Figure 39. Active Power Calculation Because LPF2 does not have an ideal brick wall frequency response (see Figure 40), the active power signal has some ripple due to the instantaneous power signal. This ripple is sinusoidal and has a frequency equal to twice the line frequency. Because the ripple is sinusoidal in nature, it is removed when the active power signal is integrated over time to calculate the energy. |
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