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LTC1702AIGN Fiches technique(PDF) 29 Page - Linear Technology |
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LTC1702AIGN Fiches technique(HTML) 29 Page - Linear Technology |
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29 / 36 page ![]() 29 LTC1702A 1702afa cycles. Over just a few cycles, however, the external components conspire to limit the speed that the output can move. Consider our typical 5V to 1.6V circuit, sub- jected to a 1A to 5A load transient. Initially, the loop is in regulation and the DC current in the output capacitor is zero. Suddenly, an extra 4A start flowing out of the output capacitor while the inductor is still supplying only 1A. This sudden change will generate a (4A)(CESR)voltage step at the output; with a typical 0.015 Ω output capacitor ESR, this is a 60mV step at the output, or 3.8% (for a 1.6V output voltage). Very quickly, the feedback loop will realize that something has changed and will move at the bandwidth allowed by the external compensation network towards a new duty cycle. If the bandwidth is set to 50kHz, the COMP pin will get to 60% of the way to 90% duty cycle in 3 µs. Now the inductor is seeing 3.5V across itself for a large portion of the cycle, and its current will increase from 1A at a rate set by di/dt = V/L. If the inductor value is 0.5 µH, the di/dt will be 3.5V/0.5 µH or 7A/µs. Sometime in the next few micro- seconds after the switch cycle begins, the inductor current will have risen to the 5A level of the load current and the output capacitor will stop losing charge. Note that the output voltage will stop dropping before the inductor current reaches this new output current level. Recall that any practical output capacitor looks like a pure capacitance in series with some amount of ESR. When a load transient hits, virtually all of the initial voltage drop at the output is due to IR drop across the ESR. The output capacitance begins to discharge at the same time and continues until the inductor current rises to match the new output current level. The output voltage, however, will turn around and start heading the right way before this happens. The next time the top MOSFET turns on, the inductor current will begin increasing linearly. This increasing current flows almost entirely into the capacitor, going through the ESR as it does so (Figure 16). Positive di/dt in the inductor causes positive dv/dt in the ESR, regardless of what the “pure” capacitance is doing. The output voltage will turn around when the positive dv/dt across the ESR exceeds the negative dv/dt across the pure capacitance. If the expected load step ( ∆I) is known, an optimum inductor value can be chosen: LV V C ESR I IN OUT ≤ () ∆ –• • APPLICATIONS INFORMATION + – – IL VOUT IOUT 1702A F16a VESR COUT VCAP VSW L + VCAP VOUT TRANSIENT HITS VOUT TURNS AROUND IL > IOUT TIME VESR IOUT IL VOUT VESR IOUT IL VCAP VOUT(NOMINAL) 1702A F16b Figure 16b. Transient Recovery Curves Figure 16a. Capacitor Parasitics Affecting Transient Recovery |
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